WebNov 11, 2013 · 1. Given the language with alphabet: {a, b, c} Draw an NFA or DFA for all the strings that have exactly twice substrings "ab" and at least on "c". I'm stuck with "exactly twice "ab"". Can somebody give me some ideas. It's also very good if you can suggest me the regular expression of this statement. automata. WebApr 6, 2024 · I have been trying solve this problem for a while now for a university assignment. I'm required to build a DFA and an NFA for the above question. So far I have been able to solve the DFA, but can not find a solution for a proper NFA after multiple tries. The solution of my DFA for the language provided above: My attempts for the NFA are …
Deterministic finite automaton - Wikipedia
WebDec 30, 2024 · Construct a minimal DFA that accepts all strings of a's and b's where each string contains 'ab' as a substring WebApr 5, 2024 · dfadesign, #gatelecture, #thegatehub, #toc design a dfa in which set of all strings can be accepted which containing "ab" as a in this video we are designing a deterministic finite automata over input alphabet {a,b} where strings contain "ab" as substring. theory of computation # *construct dfa for the string containing 'ab' as … can big blind raise in first round
DFA for strings not containing 101101 as substring
WebFor the rest, you should show that your DFA is minimal (it is). It appears that your NFA is correct, so if you convert that to a DFA and minimize it you should get your original DFA (though it would be tedious to do by hand). Don't worry about the fact that there different ways to do the NFA to DFA construction: either will work. $\endgroup$ WebApr 13, 2024 · Here are the steps for constructing the NFA algorithmically: Let's first construct the regular expression corresponding to the language L, simplest regular expression for L is ( ( a + b) ∗ a a ( a + b) ∗ b b ( a + b) ∗) + ( ( ( a + b) ∗ b b ( a + b) ∗ a a ( a + b) ∗). Now use the construction algorithm to convert a regular ... WebThe DFA accepts w if the path ends in a final state. Otherwise the DFA rejects w. The language of a DFA is the set of accepted strings. Example. The example DFA accepts the strings a, b, ab, bb, abb, bbb, …, abn, bbn, …. So the language of the DFA is given by the regular expression (a + b)b*. Start 0 1 2 a b a b a b Start 0 1 2 a, b a b a, b can bifen it be used in a spray fogger