WebAnswer (1 of 4): If the number 481 * 673 is completely divisible by 9, then what is the smallest whole number in place of *? The answer is 7 because 4+8+1+6+7+3 = 29 and as we look for a multiple of 9, we find that 29+7 = 36 and 9 divides 36. Therefore, 7 is the conventional answer. But we can ... WebIf the number 517*324 is completely divisible by 3, then the smallest whole number in the place of * will be ? (A) 2 (B) 3 (C) 4 (D) 5. Solution : Divisibility rule for 3 : If the sum of all the digits of the given number is …
Divisibility Tricks and How to Divide in Your Head
WebMain article: Divisibility Rules Divisibility rules are efficient shortcut methods to check whether a given number is completely divisible by another number or not. These divisibility tests, though initially made only for the set of natural numbers \((\mathbb N),\) can be applied to the set of all integers \((\mathbb Z)\) as well if we just ignore the signs and … Web79238 is not divisible by 8, as the number formed by the last three digits 238 is not completely divisible by 8. 875 is not divisible by 9, as the sum of all the digits, 8 + 7 + 5 = 20 is not divisible by 9. Now, let us take the … اسعار سياره الفورمولا 1
evenly divisible - Wiktionary
WebApr 11, 2024 · 16W281 83rd St, Burr Ridge, IL 60527. For Lease $19.95/SF/YR. Property Type Office - General Office. Property Size 6,500 SF. Building Class B. Year Built 2011. Date Updated Apr 11, 2024. 8 building, single story office complex located in … WebCorrect Answer: 888888888. Explanation: 12345679 x 72. = 12345679 x (70 +2) = 12345679 x 70 + 12345679 x 2. = 864197530 + 24691358. = 888888888. 10. If the number 97215 * 6 is completely divisible by 11, then the smallest whole number in … WebAnswer: Divide 763 by 57 and see what you get as a remainder Let’s do it. If as a remainder, we had got 57 instead of 22, then the number would have been divided completely by 57. This mean, we need to add something in 22 to make it 57 So, 57–22= 35 is needed to be added to 763. Then (763+35)... creditninja installment loans